Question

I NEED HELP FAST!!!


If (6^0)^x = 1, what are the possible values of x? Explain your answer.

Answer 1

You tell me.

1?
4?
\(\sqrt{2}\)?
0?
1E451?

Answer 2

i dont know

Answer 3

Hogwash. What do you think?

\(6^0\) = What?

Answer 4

1

Answer 5

See, you do know!

What's \(1^{0}\)?
What's \(1^{2}\)?
What's \(1^{4}\)?
What's \(1^{\sqrt{2}}\)?
What's \(1^{5\;million}\)?

Answer 6

1^0 = 1
1^2 = 2
1^4 = 4
1^ √ 2 = √ 2
1^5 million = 5 million

Answer 7

:) no this is not correct
we will use this rule in our problem->\(\large (m^a)^b=m^{a \times b}\)
try using it in this- \(\large (6^0)^x\)

Answer 8

Why is 1^2 = 2? I'm pretty sure 1^2 = 1.

Try again.

Answer 9

oh right

Answer 10

but can we focus on the quetion

Answer 11

We are focused on the question.

Why is 1^4 = 4? Shouldn't it be 1^4 = 1?

We should be seeing a pattern.

Answer 12

no this isn't helping with the question are just making me answer additional things

Answer 13

No, we are looking at material that should lead you to the answer - IF you are paying attention.

\(1^{\sqrt{2}} = 1\)

Has the result, so far, been anything but "1"?

Answer 14

no

Answer 15

So, if we ALWAYS get 1 - always - what might that mean?