Question

Solve using elimination.

2y - 5x = -1
x = 2y + 5

Answer 1

@phi

Answer 2

\(2y - 5x = -1\)
\(x = 2y + 5\)

I rearranged the second equation to get to
\(2y - x = -5\)

I now have
\(2y - 5x = -1\)
\(-\)
\(2y - x = -5\)

\(-4x = 4\)
\(x = -1\)

Answer 3

yes, that looks good.

Answer 4

\(-1 = 2y + 5\)
\(-1 - 5 = 2y + 5 -5\)
\(-6 = 2y\)
\(-3 = y\)

Solution
\((-1, -3)\)

Would I be correct?

Answer 5

yes

Answer 6

Okay. And when I solve it using substitution it would be
\(2y - 5x = -1\)
\(x = 2y + 5\)

\(2y - 5(2y + 5) = -1\)
\(2y - 10y - 25 = -1\)
\(-8y - 25 = -1\)
\(-8y = 24\)
\(y = -3\)

\(x = 2(-3) + 5\)
\(x = -6 + 5\)
\(x = -1\)

Solution
\((-1, -3)\)