Help please, asking for help not answers.
How many threes would be listed in the stem area of a stem-and-leaf plot with the following data? [12, 12, 22, 23, 33, 34, 36, 37, 48, 47] 2 3 4 1
\(\color{#000000 }{ \displaystyle 2|3,~5,~8 }\) woud be the way to record numbers: 23, 25, 28. 2 is the "tree" 3, 5 and 8 are the "leafs" (this is an example)
Record your numbers in the same form as I recorded 23, 25, and 28. The number behind the \(|\) is the "tree", and so, after recording the numbers this way you wil be able to determine the number of "trees"
Would the answer be 2?
Fill out the graph & count it....
For example, if you have a 11, the first number is there, then record the one.... if it's 23, record the 3 next to the 2. Get it?
Like this ? 1 | 2,2 2 | 2,3 3 | 3, 4, 6, 7 4 | 8, 7
Awesome!!
Sorry for late reply.
How many trees do you have?
That's okay! So the answer would be 2?
I explained what a "tree" is
3?
Again, \(\color{#000000 }{ \displaystyle 2|3,~5,~8 }\) woud be the way to record numbers: 23, 25, 28. 2 is the "tree" 3, 5 and 8 are the "leafs" (this is an example)
1 | 2,2 2 | 2,3 3 | 3, 4, 6, 7 4 | 8, 7
So you only count the trees?
how many times do you have a number on the left of the \(|\) ? Yes, you just count them:)
So, just 1?
|dw:1451958314465:dw|
So how many trees are there? :D
4
But I'm confused because it's asking "How many 3's are being listed" ...
threes or trees? there are three threes, and four trees.
xd
3's and the next question is how many 2's. lol
how many 2's and 3's overall in the step leaf plot, or just in leafs?
How many threes would be listed in the stem area of a stem-and-leaf plot with the following data? [12, 12, 22, 23, 33, 34, 36, 37, 48, 47]
apparently in the all plot, so threes, there are 3. two's, count them,
I see 5 twos
It's just the stem area. Which part is the stem area? the trees?
The stem is the tree
so, just the stems
and the leafs are the other numbers?
yes, the leafs are numbers on the right
okay, thank you I figured it out!
:) sorry for confusing you...
yw, tho'
thats ok! :)
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