Question

Question

Answer 1

\[\sqrt{1\pm \in} =1\pm \frac{ 1 }{ 2}\in \]

Answer 2

How?

Answer 3

What do you get when you square the right hand side ?

Answer 4

sqrt(1+-E)

Answer 5

@ganeshie8

Answer 6

How ?

Answer 7

ok, you said right side!

Answer 8

we get 1^2+-2*1/2*E(+1/2*E)^2

Answer 9

=1+-1E+-1/4E^2

Answer 10

and now????

Answer 11

If we let \(\in = 0.0001\), then \(\in^2=?\)

Answer 12

0, right?

Answer 13

oh, got it

Answer 14

Thanks a lot!

Answer 15

Why 0 ?

Answer 16

hmmm, It tends towards zero

Answer 17

when \(\in\) is small, \(\in^2\) is even smaller... so we can neglect square terms in some cases where accuracy is not needed

Answer 18

yes

Answer 19

\[\sqrt{1\pm \in} \approx 1\pm \frac{ 1 }{ 2}\in \]

Answer 20

Oh, approximately, that's why we use in Physics....

Answer 21

Well I was studing Mechanical waves, JLYK

Answer 22

Thanks a lot

Answer 23

np, mechanical waves and sound are very interesting topics. Have fun :)

Answer 24

:)