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can someone please help me? show an equation that represents the polynomial function with zeros –1, 1, and 3 (multiplicity of 2), and a y-intercept of –18?
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HI!!
since you know the zeros you can write it in factored form
since \(-1\) is a zero, one of the factors has to be \(x+1\) and so on
multiplicity 2 means the exponent on the \(x-3\) factor is \(2\) so you can start with \[a(x+1)(x-1)(x-3)^2\]
you still need \(a\) however, but that is not hard since the y intercept is -18 replace \(x\) by \(0\) and set the result equal to \(-18\) and solve for \(a\) , i.e. solve \[a(1)(-1)(-3)=-18\]
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