Question

A security man is paid at the hourly rate( R ) for the first 40 hours of work in a week. There after he
his paid at 1.25 times the hourly rate (R) for the next 16 hours and 1.5 times the hourly rate ( R) for
further hours of work in the week.
Taking the number of hours (H) and rate per hour( R) as input, the weekly wage (W) us to be
calculated. Write a program to calculate weekly wages and display it.
Write an algorithm/Java program to calculate and print the rate(R), hours(H) and wages(W).

Answer 1

@Nnesha @Zale101 @nincompoop @Whitemonsterbunny17

Answer 2

@AlexandervonHumboldt2 @Agl202

Answer 3

@ganeshie8

Answer 4

That's fairly simple all you would have to do is check if the hours are more than 40 of it is then check if it is more than 16 hours and calculate it like that so for example let's say I worked for 58 hours in that week. So 40 hours would be accounted for at normal pay then I worked 18 hours more so for the next 16 I get paid 1.25 more than what I get paid hourly and since there is still 2 hours left you must multiply 1.50 by the hourly pay and add the sum of all of that and that should give you a total. For the record im trying to help without giving you the syntax. If you have any sort of code post it here and I'll gladly take a look at it and point out mistakes or what you should add if there is anything I do notice. If you want me to clarify anything please do ask.

Answer 5

class Wages{
public static void main(String[] args) {

Scanner input = new Scanner(System.in);

System.out.println("Please enter hourly rate: ");
R = input.nextDouble();

System.out.println("Please enter number of hours worked: ");
H= input.nextInt();

if ( 0 < = H && H<= 40) {
W = R*H;
} else if ( 40< H && H <= 56 {
W = 1.25*R * H
} else if (H > 56) {
W = 1.5*R*H;

System.out.println("Total Wages are " + W);
}
}


@kva1992

Answer 6

???

Answer 7

Your if statement is wrong. It should be.
if ( H>=0 && H<= 40) {
W = R*H;
} else if ( H >=40 && H <= 56 {
W=40*R;
W=W+((1.25*R)(H-40));
} else if (H > 56) {
W = 40*R;
W = W + ((1.25*R)(16));
W = W + ((1.50*R)(H-56));

Answer 8

That should fix your issue let me know of you want me to explain.

Answer 9

System.out.println("Total Wages are " + W);

Add that after your if statement.

Answer 10

like how can u show me plsss

Answer 11

What am I showing you exactly?

Answer 12

is this right ????
public class Wages{

public static void main(String[] args) {

double a,b,c, R, W=0;
int H;

Scanner input = new Scanner(System.in);
System.out.println("Please enter hourly rate: ");
R = input.nextDouble();

System.out.println("Please enter number of hours worked: ");
H = input.nextInt();

if (H >= 0 && H <= 40) {
W = R * H;

} else if (H > 40 && H <= 56) {
W = R*40 + 1.25 * R * (H-40);
} else if (H > 56) {
W = R*40 + 1.25 * R * 16 + 1.5 * R * (H-56);
}

System.out.println("Total Wages are " + W);
}

Answer 13

@kva1992

Answer 14

CAN u show me the code in algorithm plsss
@kva1992

Answer 15

I would personally separate the calculation just so the program doesn't Compute from left to right and does it properly you could use the ABC variables at the top of the page.

Answer 16

But essentially you got it

Answer 17

ya

can u show me in pseudocode form

Answer 18

I can't exactly give you pseudocode right now I'm on my phone won't have a PC for another week or so

Answer 19

Just type exactly what your program is doing

Answer 20

Input both user driven and application driven and outputs and calculation the things that happen in the back end in order

Answer 21

And that will be your pseudocode

Answer 22

Hopefully that answered all your questions

Answer 23

thx anyways

Answer 24

No problem