Mathematics
8 Online
OpenStudy (vera_ewing):
#14
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OpenStudy (vera_ewing):
@stefanwolf1
OpenStudy (anonymous):
What form must this be in? Standard form?
OpenStudy (vera_ewing):
Yep
OpenStudy (anonymous):
Okay so your first step is to factor.
OpenStudy (anonymous):
(x-1)(x-2)(x-3)= x
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OpenStudy (anonymous):
Then you simplify it from there. Multiply two together at first and multiply that answer by the last binomial.
OpenStudy (anonymous):
You should get a degree of 3 if you do it correctly.
OpenStudy (vera_ewing):
Ok so (x^2-2x-x+2)(x-3)
OpenStudy (anonymous):
Yep! Distribute that out too.
OpenStudy (anonymous):
I have my final answer I'll check it with you.
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OpenStudy (vera_ewing):
So I got x^3 - 6x^2 + 11x - 6
OpenStudy (anonymous):
I got a different answer.
OpenStudy (anonymous):
Are you multiplying each term out?
OpenStudy (vera_ewing):
Yeah I just multiplied (x^2-2x-x+2)(x-3)
OpenStudy (vera_ewing):
And then (x^2 - 3x + 2)(x-3)
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OpenStudy (anonymous):
Don't do the second step you said. Only the first one.
OpenStudy (anonymous):
With 3 binomials, multiply the 1st two together, and take that answer and multiply it by the last binomial.
OpenStudy (vera_ewing):
I got the same thing...what did you get? and can you show your work?
OpenStudy (vera_ewing):
Because I just simplified (x^2-2x-x+2) to (x^2 - 3x + 2)
OpenStudy (anonymous):
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