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Mathematics 8 Online
OpenStudy (vera_ewing):

#14

OpenStudy (vera_ewing):

@stefanwolf1

OpenStudy (anonymous):

What form must this be in? Standard form?

OpenStudy (vera_ewing):

Yep

OpenStudy (anonymous):

Okay so your first step is to factor.

OpenStudy (anonymous):

(x-1)(x-2)(x-3)= x

OpenStudy (anonymous):

Then you simplify it from there. Multiply two together at first and multiply that answer by the last binomial.

OpenStudy (anonymous):

You should get a degree of 3 if you do it correctly.

OpenStudy (vera_ewing):

Ok so (x^2-2x-x+2)(x-3)

OpenStudy (anonymous):

Yep! Distribute that out too.

OpenStudy (anonymous):

I have my final answer I'll check it with you.

OpenStudy (vera_ewing):

So I got x^3 - 6x^2 + 11x - 6

OpenStudy (anonymous):

I got a different answer.

OpenStudy (anonymous):

Are you multiplying each term out?

OpenStudy (vera_ewing):

Yeah I just multiplied (x^2-2x-x+2)(x-3)

OpenStudy (vera_ewing):

And then (x^2 - 3x + 2)(x-3)

OpenStudy (anonymous):

Don't do the second step you said. Only the first one.

OpenStudy (anonymous):

With 3 binomials, multiply the 1st two together, and take that answer and multiply it by the last binomial.

OpenStudy (vera_ewing):

I got the same thing...what did you get? and can you show your work?

OpenStudy (vera_ewing):

Because I just simplified (x^2-2x-x+2) to (x^2 - 3x + 2)

OpenStudy (anonymous):

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