Anyone good with Geometry? Will medal and fan
Prove that a line parallel to one side of a triangle divides the other two sides proportionally. Be sure to create and name the appropriate geometric figures
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We are going to use that triangle
So ABC? and then DE divides the triangle?
Well, we know that DE is parallel to BC. Also, the triangles ADDE and ABC are similar. This is because, angle A is shared by both triangle. AND angle ADE is equal to angle ABC, they are corresponding angles. So, by using the two angles postulate, ADE and ABC are similar. We do: \(AB / AD = AC / AE\) \((AD+DB) / AD = (AE + EC) / AE\) \(1 + DB / AD = 1 + EC / AE\) Then, you want to subtract 1: \(DB / AD = EC / AE\) This then proves that a line parallel to one side of a triangle divides the two other sides proportionally.
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