What is the equation of the graph below?
@StudyGurl14
here
Please post the graph right away, before you contact another user.
Okay, first step. Find the vertex.
which would be 2, right?
The vertex is a point, so your result must be a point: (x,y)
^
(3,2)?
Once you have the vertex, what do you do with it?
StudyGurl: feel free to take over if y ou wish.
i input it into the equation
@StudyGurl14
Okay, so the equation of a parabola: \(\Large y=a(x-h)^2+k\) where (h,k) is the vertex
yes
so plug in your vertex into the equation
ok I got y=a(x-3)^2+2
Do you have a graphing calculator? If so, graph your function. Does your graph resemble the given graph?
no, i do not own a graphing calculator, sorry
What is your value for a? How did you obtain it?
a is the slope? I forget
It's a multiplier, but it's not a slope in the way we usually think of slope.
yep. now we have to find a. to find that, first we need another point on the parabola. can you find one?
no, a is not the slope
Does the graph open up or down? What does this question have to do with the value of a?
1 @StudyGurl14 and it opens up @mathmale
sorry, but I think not. I see the given graph opening down.
^
remember, points are (x,y), not just one number
You can find various math utilities online that will graph functions for youi. Please go to http://www.wolframalpha.com/input/?i=y-2%3D-%28x-3%29%5E2 and take a look. What is the value of a?
what point is this?
-2 @StudyGurl14
yes (1,-2)
plug that point into the equation y= a(x - 3)^2 + 2 and solve for a
what would a and x be? @StudyGurl14
Your equation is y= a(x - 3)^2 + 2 and your goal is to find the valule of "a". In previous work you found that another point on the given graph is (1,-2). Substitute 1 for x and -2 for y in y= a(x - 3)^2 + 2. This will leave you with an equation in "a" alone. Try this, please. Solve for "a."
would i distribute "a"?
No. Your best bet: "Substitute 1 for x and -2 for y in y= a(x - 3)^2 + 2."
ok, so then i would get -2=a(1-3)^2+2 correct
Yes. Simplify this as much as possible. See whether you can solve it for a.
i got -2=2a+2, which would then be -2=4a
Have you tried solving for a?
i got a=-0.5
It's important that you have a way to graph equations such as this one. If your "a" is -0.5, then your equation is y=-0.5(x-3)^2 + 2. Double check. Do you agree with this or not?
no, it would be more complicated to graph and should be a whole number for this one
I'm telling you I believe it is important that you have a way of graphing equations. So much information can be obtained from good graphs. Have you spoken with your parents about buying a graphing calculator, e. g., a TI-84?
no, but how do i solve this problem NOW without the graphing calculator...
The equation is y=-0.5(x-3)^2 + 2. I would liek for you to use an online utility to graph this. go to this web page:
ok I'm putting in the equation now
ok, I got x=3
sorry , i didn't include my answer choices: y = − (x + 2)2 + 2 y = − (x − 3)2 + 2 y = (x − 2)2 + 2 y = (x + 3)2 + 2
Did you go to wolframalpha.com?
yes
thank you. type in y-2=(x-3)^2. You could copy that equation and paste it into the yellow box on wolframalpha.
When you've finished doing that, either hit RETURN or click on the = symbol at the right end of the box.
ok, I did correctly now I got this equation: y=(x-3)^2+2
@mathmale but that doesn't correlate with my answer choices
Unfortunately, that means your equation is not completely correct. Try typing this equation into wolframalpha: y-2=-(x-3)^2
ok i typed it in correctly, but i don't know which equation i should be looking at
I want you to compare the graph given you by wolframalpha to the graph given in your math problem. If they are exactly the same, then y ou have found the correct "a."
no, they are not the same...
In what way are the 2 graphs different?
I'm asking you to compare graphs, not to compare equations.
oh ok, then they are in fact the same
then you have found the correct "a" value. Type out the whole equation of the curve you were given. y
ok,,, how do i do that??!! Your directions are always cryptic and not very helpful.
it takes 30 minutes to solve one problem whereas, with other help its much faster and i learn more
I've given you a considerable amount of time. If you feel the need to be critical now, then I may choose to give my time and experience to someone else. I've typed the equation again and again. Go back and look thru our conversation. It begins with y-2. The goal of this problem was to determine the equation of the given curve.
OK. I'm sorry you're not satisfied. Good evening.
ok, I know you are trying to help, but it is very hard to understand
Sometimes when a student has trouble understanding, it is as much or more the lack of preparation and participation on the part of the student as it is any defects in the teacher's approach. I had enjoyed working with you up until a few minutes ago, but when you reward my efforts with complaints and negative comparisons of me with other tutors, I lose interest almost immediately. Keep this in mind next time you criticize someone who is trying to help you.
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