Please Explain Write a polynomial function for the set of zeros: x=-3,4,7
Well since all of those x's are zeroes, you can write equations for each of them and then multiply them together to get the polynomial
do you know how to write expressions for each of the roots?
Still dont get it... no i dont know how to
okay. So to write an equation for a root you write in the form (x-y) where y is the root. Now try to write expressions for all of the other roots.
??? so it'd be (x+3) for the first one and then i would set it equal to zero?
It would be like that but remember they are expressions so they won't be set equal to anything
If you know how to solve quadratic equations by factoring you know that you have to set the expression in the parentheses equal to zero to get your root. This is like that, but in reverse. (If you don't know how to do that just don't bother)
can you give me an example of how it would be done?
so if you have the roots x=3,4,5,-6 then the expressions would be (x-3), (x-4), (x-5), and (x+6). To find an equation with all of the x-values as roots, then you would multiply the expressions together and expand
So with my example 1 possible equation would be (x-3)(x-4)(x-5)(x+6). (I didn't bother expanding this because it would take a long time.)
Ok thank you i think i get what you mean know thanks :)
So what would the answer be?
can i ask one more question?
Sure.
if it tells me to expand the binomial of (1-2x)^2 would i repeat the equation in parenthesis twice and then foil?
Yes. By foil do you mean first outside inside last? I'm pretty sure that's what it means. I don't use that method. I just distribute.
yea thats what it means. so back to the first question i have them set in the paranthesis and now i should foil like im supposed to do in the second question right? then add like terms and i should get my equation
Yes. (1-2x)(1-2x). Then just FOIL and add like terms
no i meant for the first question i asked
the (x+3) (x-4) (x-7)
Oh yeah. Well then: (x+3)(x-4)(x-7). FOIL the first 2 expressions then add like terms. Then FOIL with the last expression. You just be FOILing a quadratic with a linear expression to get a cubic expression which is your answer
Any other questions?
no but can i check back in with you to check my answer?
x^3-8x^2-5x+84 is what i got
This is right.
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