Question

Find the perimeter of the image below:

Figure PQRST is shown.
P is at negative 2, 11.
Q is at negative 4, 5.
R is at 2, 0.
S is at 1, 7.
T is at 8, 7.

37 units
38 units
39 units
40 units

Answer 1

@matricked

Answer 2

To find the distance (or length) between the points (x1,y1) and (x2,y2)
use the following formula sqrt( (x2-x1)^2 +(y2-y1)^2)

Answer 3

I saw that somewhere, but I'm not sure how to use it.

Answer 4

for example to find ST ( S-->(1,7) and T-->(8,7) )
ST = sqrt ( (8-1)^2 +(7-7)^2)=sqrt( (7^2+0^2) = sqrt(49+0)=sqrt(49)=7 units

Answer 5

in a similar manner you need to find the length of the other sides and then add them all

Answer 6

so if ST = 7, would PT be something like 10.8?

Answer 7

yup

Answer 8

so then SR would be next, right?

Answer 9

yup

Answer 10

and what one would pair with Q? or would Q be on its own?

Answer 11

you need to find PQ and QR

Answer 12

you need two points to find the distance using the above formula

Answer 13

I don't think I did SR right because it came out to 7...

Answer 14

it is little more than 7 units

Answer 15

well I'm not sure where I made an error... it may also be because I'm doing geometry near midnight and I'm not thinking properly

Answer 16

R is at 2, 0. S is at 1, 7.

SR=RS= SQRT((1-2)^2+(7-0)^2) = SQRT( (-1)^2 + 7^2) =SQRT(1+49)=SQRT(50)
=SQRT(5*5*2)=5*SQRT(2)=7.071 APPROX.

Answer 17

but we wouldn't round it?

Answer 18

YUP YOU CAN

Answer 19

to the nearest whole? because that'd be 7.
or it would be rounded to 7.1

Answer 20

7.1

Answer 21

so PQ is next. let me try this one.

Answer 22

PQ = 8.485, which rounds to 8.5?

Answer 23

PQRST

FIND PQ, QR, RS, ST AND TP AND THEN ADD ALL THE RESULTS

Answer 24

YOUR ANSWER FOR PQ CONTAINS ERRORS

Answer 25

how much off am I?

Answer 26

CAN YOU TELL ME FOR PQ WHAT ARE THE VALUES FOR
X1
Y1
X2
Y2 ?

Answer 27

X1 - 2
x2 - negative 4
y1 - 11
y2 - 5
?

Answer 28

GO AHEAD
IS YOUR X1 2 OR (-2)
THEN
X2-X1 =?
Y2-Y1=?

Answer 29

x1 is a positive 2.

so
x2 - x1 = (-4) - 2 = negative 6
y2 - y1 = 5 - 11 = negative 6
?

Answer 30

P is at negative 2, 11. Q is at negative 4, 5.

Y2-Y1 IS CORRECT

Answer 31

BUT I AM CONFUSE FOR X1
IS YOUR
X1=2 OR
X1=-2

IF YOU SAY X1=2 THEN X2-X1 IS CORRECT OTHERWISE NO

Answer 32

x1 is 2

Answer 33

BUT INYOUR POST YOU HAVE STATED negative of 2
OK LEAVE IT
YOUR X2-X1 IS CORRECT AS WELL AS PQ=8.5 IS ALSO CORRECT

Answer 34

okay so next is QR then

Answer 35

GO ON

Answer 36

would it be -11?

Answer 37

no
you have added 6 and 5

Answer 38

negative 6 and 5, yeah

Answer 39

first add the term after squaring and then take the root of the sum

Answer 40

so if I had the
x1 = 2
x2 = negative 4
y1 = 0
y2 = 5

Answer 41

then
x2 - x1 = negative 6
y2 - y1 = 5
right?

Answer 42

it will be sqrt(36+25)=sqrt(61)= 7.81 appx...

Answer 43

OH, I see what I forgot to do.

Answer 44

ok

Answer 45

Okay so
PT = 10.8
ST = 7
SR = 7.1
PQ = 8.5
QR = 7.8 (7.81)

and we add them all together?

Answer 46

the best thing is that now you are able to find the distance between the two points

Answer 47

FIND PQ, QR, RS, ST AND TP AND THEN ADD ALL THE RESULTS

Answer 48

I found SR, which is the same thing as RS, right?
same with PT vs. TP?

Answer 49

@matricked ?

Answer 50

adding the numbers up gave me 41.2