Question

Eli has 8 black pens and 5 blue pens in his desk drawer. He also has 3 yellow highlighters, 4 green highlighters, and 5 pink highlighters in his pencil case. If he chooses one pen and one highlighter without looking, what is the probability that he will get a blue pen and he will not get a yellow highlighter?
5/52
6/13
2/13
15/52

Answer 1

First find how many pens are there in total and in each colour?

Answer 2

no there are 13 pens and 12 high;fighters

Answer 3

okay now what would you normally do next?

Answer 4

Okay

Answer 5

yes ^

Answer 6

Idk what to do to solve it

Answer 7

now what is the probability of picking a blue pen from the 13 pens?

Answer 8

5/13?

Answer 9

well then you need to reveiw the lesson

Answer 10

P(blue pen) = number blue pens / total number of pens

Answer 11

or atleast write notes next time :)

Answer 12

5/13 is correct

Answer 13

Mc, if you're not going to help don't comment. I came here because I didn't know how to solve the problem. I'm behind in class, so I don't know all the material.

Answer 14

So there is a 3/12 chance fora yellow highlighter?

Answer 15

now the next thing to work out is the probability of not getting a yell highlighter

Answer 16

3/12 is for getting a yellow - you want the probability of getting any other colour but yellow

Answer 17

9/12?

Answer 18

yes dead right

Answer 19

So I just multiply 9/12 * 5/13?

Answer 20

now since the 2 picks are independent of each other to get p(blue pen and non yellow) you multiple the probe

Answer 21

yes correct \good job

Answer 22

I got 15/52 when I multiplied them, is that right?

Answer 23

yep

Answer 24

Yay thanks! I've got a bunch of these kind of problems so this really helps me. :)

Answer 25

yw

Answer 26

when looking at combined probabilities the operative words are ADD and OR
add = multiply probabilities
or = add probabilities