whats 2 to the -23 power devided by seven
You are expected to show your own efforts before asking for help.
but its hard
ok, so i know you have to multiply 2 by -23 first
Absolutely not! 2^(-23) is exponentiation, not multiplication.
@ddelph1 Break it up into pieces. First, complete the problem \[2^{-23}\]
@mathmale is correct @ddelph1 , this is not a multiplication problem.
ooooooopppssss
my b
@mathmale Sorry, I forgot. HOORAY!!!! MATHMALE IS ONLINE!!!!! lol
Now, @ddelph1 Do you know how to solve equations with exponents? You know what, it might be better to write the equation in actual symbol and numbers, instead of words.
idk how
\[\frac{ 2^{-23} }{ 7 }\]
ddelp1: You've asked the question. If you seriously want to arrive at an answer, start thinking and showing more work of your own.
Use PEMDAS Parentheses Exponents Multiplication Division Addition Subtraction According to PEMDAS, you have to solve 2^(-23) first, and then divide that answer by 7
What is \[2^{-23}\]
im trying. Calm down
@ddelph1 Openstudy is not a place where you will just get the answers and leave. We are only here to guide you to your answers, not to give you the answers.
Now, what is \[2^{-23}\]
-8,388,608 i think
How did you calculate that?
ok so i think i did it right this time
-16777216
How did you calculate that? Show your work @ddelph1 .
@mathmale Am I doing this correctly? Normally I just get help on OS, i don't generally give help
2x-2 23 times
I'm sorry, what?
2 multiplied by -2 23 times
Okay, so complete the problem.
@mathmale It's actually been a while since I've done problems with negative exponents, what he is doing is correct, right?
2^23 would signify "2 used as a multiplicand 23 times." 2^2=2*2 =4, 2^3 = 2*2*2, and so on. "2 multiplied by -2 23times is not correct.
I got it!!!!!!!!!!!!!!
-2396745.142
baboomn
that isnt direct that isnt the answer @Needhelpstudying
but whatever floats your boat
I'm surprised no one has mentioned \[\large \sf a^{-n}=\frac{1}{a^n}\]
2^(-23) is exponentiation, not multiplication. Isn't that an application of \[\large \sf a^{-n}=\frac{1}{a^n}?\]
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