What is the value of the range of the function f(x)=x^2+2 for the domain value of 1/4?

Question

caroline1218 · Answer

A. y=2
B. y = 2 1/4
C. y = 2 1/8
D. y = 2 1/16

imqwerty · Answer

domain represents the value that $f(x)$ can take
and range represents the value that $x$ can take
and we are given that domain is $\large \frac{1}{4}$  so therefore ->

$\large f(x)=x^2+2$

we have $f(x)=\large \frac{1}{4}$  so put it in the equation we get this-

$\large \frac{1}{4}=x^2+2$  

now try to find  the value of $x$ from here :) that will be your range

caroline1218 · Answer

Wait, I believe it is y = 2 1/16 or D

caroline1218 · Answer

Is D correct?

skullpatrol · Answer

Yes.

caroline1218 · Answer

Ok, thank you :)

skullpatrol · Answer

Thanks for asking :-)

imqwerty · Answer

@skullpatrol  but solving that isn't giving real values of x :|

skullpatrol · Answer

You have to solve for y given x=1/4.

imqwerty · Answer

oh kay i said the opposite damn