Question

What is the value of the range of the function f(x)=x^2+2 for the domain value of 1/4?

Answer 1

A. y=2
B. y = 2 1/4
C. y = 2 1/8
D. y = 2 1/16

Answer 2

domain represents the value that \(f(x)\) can take
and range represents the value that \(x\) can take
and we are given that domain is \(\large \frac{1}{4}\) so therefore ->

\(\large f(x)=x^2+2\)

we have \(f(x)=\large \frac{1}{4}\) so put it in the equation we get this-

\(\large \frac{1}{4}=x^2+2\)

now try to find the value of \(x\) from here :) that will be your range

Answer 3

Wait, I believe it is y = 2 1/16 or D

Answer 4

Is D correct?

Answer 5

Yes.

Answer 6

Ok, thank you :)

Answer 7

Thanks for asking :-)

Answer 8

@skullpatrol but solving that isn't giving real values of x :|

Answer 9

You have to solve for y given x=1/4.

Answer 10

oh kay i said the opposite damn