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Mathematics 14 Online
OpenStudy (andrewkaiser333):

need help with arithmetic series

OpenStudy (andrewkaiser333):

\[{A}_1=4; d=7; S _{n}=228=EC\]

OpenStudy (andrewkaiser333):

Please help me solve step by step so i know what to do for others.

OpenStudy (andrewkaiser333):

@Hero

OpenStudy (andrewkaiser333):

anyone???

OpenStudy (hossamhoussien):

you here wanna find (n) value, right?

OpenStudy (andrewkaiser333):

that and athe upside down ^n

OpenStudy (hossamhoussien):

\[S_{n}=\frac{ n }{ 2 }(2a_{1}+(n−1)d)\] Use this formula to find n

OpenStudy (hossamhoussien):

you know how to do it, right?

OpenStudy (andrewkaiser333):

no not really

OpenStudy (hossamhoussien):

ok you have (a) value which is =4 and also have d-value = 7 and have Sn=228 So plug each value into your formula and tell me what you got

OpenStudy (andrewkaiser333):

228=n/2(2(4)+(n-1)7)

OpenStudy (andrewkaiser333):

correct?

OpenStudy (hossamhoussien):

yea since you have only one variable now you have to solve it for (n)

OpenStudy (andrewkaiser333):

k how

OpenStudy (hossamhoussien):

\[228=\frac{ n }{ 2 }[(2\times4)+(n-1)\times7]\] \[228=\frac{ n }{ 2 }(8+7n-7)\] Multiplying both sides by 2 : \[456=8n+7n^2-7n\] arrange now you get : \[7n^2+n-456=0\] Final step is to get n value(tell me if you don't know how to do it)

OpenStudy (andrewkaiser333):

is 0 An?

OpenStudy (andrewkaiser333):

or am i missing soemthing from this

OpenStudy (andrewkaiser333):

something8

OpenStudy (andrewkaiser333):

something*

OpenStudy (hossamhoussien):

yea it will be 8

OpenStudy (andrewkaiser333):

wait N is 8

OpenStudy (hossamhoussien):

\[S _{n}=228\] \[S _{8}=228\]

OpenStudy (andrewkaiser333):

ok csn you do like a recap of the whole thing so i can write this down so i dont miss anything on here?????

OpenStudy (andrewkaiser333):

of the step by steps

OpenStudy (andrewkaiser333):

for finding everything

OpenStudy (andrewkaiser333):

please i am not trying to miss anything

OpenStudy (andrewkaiser333):

hello?

OpenStudy (hossamhoussien):

OpenStudy (andrewkaiser333):

that is the whole thing yes???

OpenStudy (andrewkaiser333):

@HossamHoussien

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