Question

Need help with the info on these two graph points: (-3,2) and (2,-1).
Info I need for it is:
*Equation for the line(That two points made) in slope-intercept form, standard form, & point slope form.
*An inference about the steepness and direction of the line compared to the value given for slope.

i'll put a picture of the line the two points make V V

Answer 1

anyone please

Answer 2

Slope-intersect form : \[y=mx+c\]=================
\[y=\frac{ -3 }{ 5 } x+\frac{ 1 }{ 5 }\]=================
General (standard) Form : \[ax+by-c=0\]
Where m=-a/b
===============\[3x+5y−1=0\]===============
Point slope Form :
\[(y-y _{1})=m(x-x _{1})\]
\[where: (x _{1},y _{1}) point\]
===============
\[(y-(-3))=\frac{-3}{5}(x-2)\]===============

Answer 3

Thank you! Can you help me with the last part? @HossamHoussien

Answer 4

steepness is simply the slope (m)
you can conclude the direction from the attached pic

Answer 5

did you get it?

Answer 6

@gabby1214 ??

Answer 7

Ohh I think so, does that mean it would be a negative slope because the line is going down

Answer 8

ya u r correct @gabby1214

Answer 9

U can also check it with value of m (slope)..here m=-3/5 notice the negative sign...

Answer 10

yea you're correct