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Find the 62nd term of the following arithmetic sequence 3,7,11,15,....
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You have to add 4 to 3 62 times and that's how you get your answer.
A formula applying to arithmetic sequences that I learned decades ago is l=a+(n-1)d, where l is the last term, a is the first term, n is the number of terms and d is the difference from one term to the next following term.
Find the 62nd term of the following arithmetic sequence 3,7,11,15,.... Let's check whether this formula "works." In the arith sequence given above, a=3, l=7 and d=4. We should be able to predict that the 4th term is 15. l=a + (n-1)d becomes l=3+(4-1)4 = 3+(3)4=15. correct. Now predict the 62nd term. Note: Please let @aduller have first stab at this!
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