Question

I'm so incredibly lost. Will post below how I think I'm supposed to solve it.

Answer 1

\[\frac{ 9 }{ \sin80 } = \frac{ 5 }{ sinB }\]

Answer 2

http://prntscr.com/9ondop

Answer 3

Sorry, there's the problem.

Answer 4

So from what we learned, I can set the equation up like the above way I had it set up. So don't I just want to divide 9/sin80 by 5?

Answer 5

Am I on the right track or..?

Answer 6

it's flipped, isn't it?

Answer 7

\[\frac{ Sin80 }{ 9 } = \frac{ SinB }{ 5 }\]

Answer 8

\[\sin^-1(\frac{ \sin80(5) }{ 9 }) = measure of ang\]

Answer 9

sorry
meassure of angle B?

Answer 10

change m<A = 80 radians
into degrees