State the domain and range of this square root function: y=3(sqrtx+2)+1. Then describe the transformations that you would do to get to the parent function.

Question

anonymous · Answer

the quantity inside the square root has to be equal to 0 or greater than 0.

It can't be negative.

anonymous · Answer

your function is,

$y=3\sqrt{x+2}+1$

corrrect?

anonymous · Answer

yes

anonymous · Answer

What is inside the square root in your case?

anonymous · Answer

i dont know its just x so far. i have to find the domain and range and describe what i do to get the parent function

anonymous · Answer

@HanaMalik

priyar · Answer

to find the domain u have to make sure x+2 doesn't take negative values

anonymous · Answer

it doesnt as far as i know

priyar · Answer

no...what if x takes the value 1?

priyar · Answer

sorry,-1

mathmale · Answer

$$y=3(sqrtx+2)+1\rightarrow 3\sqrt{x+2)}+1$$

mathmale · Answer

We should agree on the accuracy of the problem statement before talking about how to find the domain and range of this function.  Does what I've written, above, correctly reflect the original problem?  If not, make the necessary changes.

mathmale · Answer

$$y=3(sqrtx+2)+1\rightarrow 3\sqrt{x+2}+1$$

mathmale · Answer

Please look carefully at $$y=3\sqrt{x+2)}+1$$ and ask yourself what values x may take on  and which it may not.

@priyar 's suggestion is a good one:

priyar 
to find the domain u have to make sure x+2 doesn't take negative values

priyar · Answer

yes thats what i told..