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First step. Move the sqrt in the denominator to the numerator, and convert the square roots to exponents
Tell me what you get.
\[(x ^{1/2}-1)^2x ^{-1/2}\]
yep. okay, now combine and simplify it as much as you can. tell me what you get
\[(x-2x ^{1/2}+1)x ^{-1/2}\]
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Yep, but distribut ethe x^-1/2 too
\[x ^{1/2}-2+x ^{-1/2}\]
Excellent. Now find the anti-derivative of that.
That'll be your final answer.
\[2x ^{3/2}/3-2x+\sqrt{x}\]
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not quite. The last term isn't correct. make sure to divide by 1/2
But I think you have it mostly. Good job. :) I have to go now. Good luck
thanks for the help!
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