Question

This is an easy question but, can someone help me?
I just really can't understand how to find an answer
If 3x^2-x-14 (with quadratic formula please)

Answer 1

Okay, you need to find the values of \(x\) that make \[3x^2-x-14=0\]You can use the quadratic formula for that, which states that if you have a quadratic of the form\[ax^2+bx+c = 0,\ a\ne0\]the solutions are given by \[x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Compare your equation with the first equation I gave, determine the values of \(a,b,c\), then plug them into the formula and grind out the answer(s).

Answer 2

Hint: x+2 is a factor.

Answer 3

\(x+2\) is a factor, but that isn't much help if you're supposed to do the problem in a way that doesn't involve factoring...