How do you change y=x^2-2x-3 to vertex form?
The formula is a(x-h)^2 + k
I add 3 to both sides and then I don't know what to do after that.. So now I have y+3=1x^2-2x
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OpenStudy (wendy.ivette11714):
@jabez177 @KendrickLamar2014 @Awolflover1
OpenStudy (er.mohd.amir):
x^2-2x+1=(x-1)^2
OpenStudy (anonymous):
So it's 1(x-1)^2-3? @Er.Mohd.AMIR
OpenStudy (er.mohd.amir):
No add -1
OpenStudy (anonymous):
complete the square as above
y=1(x^2-2x+1-1)-3
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OpenStudy (er.mohd.amir):
1(x-1)^2-4
OpenStudy (anonymous):
Why do I add -1? @Er.Mohd.AMIR
OpenStudy (er.mohd.amir):
for complteing square add 1 and therefore subtract 1 for balence the eq.
OpenStudy (er.mohd.amir):
a2+b2-2ab=(a-b)2
so x2-2.x.1+1-1=(x-1)2-1
OpenStudy (anonymous):
Wait, the equation is x^2-2x-3, plus 3 on each end. y+3=x^2-2x then y+3=1(x-1)^2 but im confused on where the 3 goes.. @Er.Mohd.AMIR
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