Which relation is a function?
A.
x −2 −2 0 1 8
y 3 6 0 0 9
B.
x 3 5 7 14 14
y −9 5 −9 1 2
C.
x −3 4 5 9 12
y 1 −2 −2 0 7
D.
x −7 −5 6 8 8
y −3 8 1 1 −9
plrase help due today
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OpenStudy (anonymous):
first things first do you have a clue what a function is
OpenStudy (whpalmer4):
A function is a relation where each value of \(x\) has only 1 associated value of \(y\). If \(x\) repeats, it must always have the same value of \(y\) with each repeat.
OpenStudy (rockycatsrule):
yea i know that
OpenStudy (rockycatsrule):
help @AlexandervonHumboldt2
OpenStudy (rockycatsrule):
can you help me
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OpenStudy (whpalmer4):
So, look at the data. That's all you need to do.
OpenStudy (whpalmer4):
Look at A:
x −2 −2 0 1 8
y 3 6 0 0 9
Does the same value of \(x\) appear more than once?
OpenStudy (rockycatsrule):
i think the anser is maybe d
OpenStudy (anonymous):
you have to think
OpenStudy (whpalmer4):
let's just work through it on all 4, and you'll understand it.
So, looking at A, did the same value of \(x\) appear more than once?
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OpenStudy (anonymous):
so does the same value of x come into a twice
OpenStudy (anonymous):
sry
OpenStudy (anonymous):
said the same thing
OpenStudy (rockycatsrule):
i have already tried to solve it but i could not figer out what the answer would be i think it is d but not sure
OpenStudy (anonymous):
so lets go through it
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OpenStudy (rockycatsrule):
kk
OpenStudy (whpalmer4):
Come on, look at this table.
x −2 −2 0 1 8
y 3 6 0 0 9
Does the same value of \(x\) appear more than once? Yes or no?
OpenStudy (rockycatsrule):
yes
OpenStudy (rockycatsrule):
???
OpenStudy (whpalmer4):
Okay. Do those both have the same value of \(y\) underneath them?
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OpenStudy (rockycatsrule):
yes???
OpenStudy (anonymous):
perfect
OpenStudy (whpalmer4):
Do you know how to read a table? What is the first entry in the row for x?
OpenStudy (rockycatsrule):
-2
OpenStudy (whpalmer4):
@raceter444 that's not perfect, that's incorrect :-(
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OpenStudy (whpalmer4):
and the first entry in the row for \(y\)? what is that?
OpenStudy (rockycatsrule):
3
OpenStudy (whpalmer4):
that's correct. Now let's do the same thing, except give me the second entry in the row for \(x\) and the second entry in the row for \(y\)
OpenStudy (anonymous):
ill get back to the point
OpenStudy (anonymous):
im the fun cop u are the corect cop k
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