Ask your own question, for FREE!
Physics 13 Online
OpenStudy (anonymous):

'You toss a marble straight up into the air with a speed of 1.3 meters per second. How long does it take the marble to reach its highest point?'

OpenStudy (kkutie7):

think about the movement of the marble and draw a picture

OpenStudy (anonymous):

we know that a= -9.8 m/s^2. we know initial velocity is 1.3 m/s. when it reaches its highest point, we know final velocity is 0. so what would be the height? use this equation: (final velocity)^2 = (initial velocity)^2 + 2(acceleration)(height) and then solve for the height!

OpenStudy (shamim):

Required equation is v=u-gt

OpenStudy (shamim):

U know at highest point The velocity v=0

OpenStudy (shamim):

u=initial velocity

OpenStudy (shamim):

g=gravitational acceleration

OpenStudy (shamim):

Time=t=?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!