Question

-6x^2=-48
What is "x" using square root terms

Answer 1

1. \[-6x ^{2} = -48\]

we've got to isolate x first by dividing both sides by -6

2. \[x ^{2} = \frac{ -48 }{ -6 }\]

3. \[x^{2} = 8\]

now we take the square root of both sides because that's the inverse/opposite of x^2

\[\sqrt{x ^{2}} = \sqrt{8}\]

this gives us the following

\[x = \sqrt{8}\]

to simplify the square root of 8, we can try to simplify by doing this.
\[\sqrt{8} = \sqrt{4*2} = \sqrt{4}*\sqrt{2} = 2\sqrt{2} = x\]

Answer 2

@Photon336 --- ATTENTION please ! hope you know that than

x^2 = b so than

x_1,2 = +/- sqrt(b) - yes ?