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graph y=2x-x^3. How many turning points are there?
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\[ y=2x-x^3\] \[ y'=2-3x^2 = 0, \implies x^2 = \dfrac{2}3{}, \quad x = \pm \sqrt{\dfrac{2}3{}}\] go from there?
The x^3 term is negative so the graph will have a downward trend as it goes from left to right. And there should be 2 turning points. So this eliminates A and B. What graph (C or D) has a trend that goes downward?
@elvisiscool69
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c?
Yes! Correct.
really?!
yeah
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