Mathematics
22 Online
OpenStudy (anonymous):
4r^2-15r+9
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OpenStudy (xapproachesinfinity):
factoring?
OpenStudy (anonymous):
yea i got down to this so far
OpenStudy (anonymous):
36r^2-15r+9
OpenStudy (xapproachesinfinity):
how did you aapproach the problem first hand when you tried
OpenStudy (anonymous):
multiplied the first and last number
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OpenStudy (xapproachesinfinity):
are you doing 36r^2-15r+9
or 4r^2-15r+9
OpenStudy (anonymous):
the bottom one
OpenStudy (xapproachesinfinity):
oh i see so you doing ac method
good
so you did 36x9
OpenStudy (anonymous):
yep
OpenStudy (anonymous):
i just forget the rule after that
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OpenStudy (xapproachesinfinity):
324 is the result correct
OpenStudy (anonymous):
i need the factor not the final number
OpenStudy (xapproachesinfinity):
yes im just posting the number so we agree that its 324
OpenStudy (xapproachesinfinity):
we will look at the factor that give as the middle term
OpenStudy (anonymous):
oh no itd be 4 * 9
which is where i got the 36 from
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OpenStudy (xapproachesinfinity):
oh now you confused me
so we are doing 4r^2-15r+9 right?
because you wrote a totally different expression
OpenStudy (anonymous):
4r^2-15r+9
then (4)(9)=36
so 36r^2-15r+9
OpenStudy (anonymous):
and now what
OpenStudy (xapproachesinfinity):
nope that's no legible to do
36r^2-15r+9 is a different problem you have created
just stop at 4x9=36 and look for all the factor that add to -15
OpenStudy (xapproachesinfinity):
factor of 36 are ?
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OpenStudy (anonymous):
12 by 3
OpenStudy (xapproachesinfinity):
correct and they must be both negative -12 and -3
OpenStudy (xapproachesinfinity):
now what we do is rewrite that middle part as -15x=-12x-3x
OpenStudy (xapproachesinfinity):
that supposed to be r not x sorry
OpenStudy (xapproachesinfinity):
so the expression becomes 4r^2-12r-3r+9
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OpenStudy (xapproachesinfinity):
regroup like this (4r^2-12r)-(3r-9)
OpenStudy (anonymous):
is the answer (2r-12)(2r-3)
OpenStudy (xapproachesinfinity):
then let me ask you what can i do with the first parenthesis
OpenStudy (xapproachesinfinity):
no you are going fast! do it in step to get it
OpenStudy (xapproachesinfinity):
so 4r^2-12r what can we factor
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OpenStudy (anonymous):
2
OpenStudy (xapproachesinfinity):
why 2?
OpenStudy (anonymous):
4r^2
OpenStudy (anonymous):
*4r
OpenStudy (anonymous):
4r(r-3)
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OpenStudy (xapproachesinfinity):
good!
OpenStudy (xapproachesinfinity):
and for this 3r-9
OpenStudy (anonymous):
3
OpenStudy (xapproachesinfinity):
yep
OpenStudy (anonymous):
(4r-3)(-3r-3)
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OpenStudy (xapproachesinfinity):
no you forgettting something
this is what we have so far 4r(r-3)-3(r-3)
OpenStudy (anonymous):
mmmm true
OpenStudy (anonymous):
(4r-3)(r-3)
OpenStudy (xapproachesinfinity):
yay!!
OpenStudy (anonymous):
thanks I appreciate. awesome help and way to stick with me b!
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OpenStudy (xapproachesinfinity):
you did great :)
OpenStudy (xapproachesinfinity):
no problem feel free :)