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Mathematics 22 Online
OpenStudy (anonymous):

4r^2-15r+9

OpenStudy (xapproachesinfinity):

factoring?

OpenStudy (anonymous):

yea i got down to this so far

OpenStudy (anonymous):

36r^2-15r+9

OpenStudy (xapproachesinfinity):

how did you aapproach the problem first hand when you tried

OpenStudy (anonymous):

multiplied the first and last number

OpenStudy (xapproachesinfinity):

are you doing 36r^2-15r+9 or 4r^2-15r+9

OpenStudy (anonymous):

the bottom one

OpenStudy (xapproachesinfinity):

oh i see so you doing ac method good so you did 36x9

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

i just forget the rule after that

OpenStudy (xapproachesinfinity):

324 is the result correct

OpenStudy (anonymous):

i need the factor not the final number

OpenStudy (xapproachesinfinity):

yes im just posting the number so we agree that its 324

OpenStudy (xapproachesinfinity):

we will look at the factor that give as the middle term

OpenStudy (anonymous):

oh no itd be 4 * 9 which is where i got the 36 from

OpenStudy (xapproachesinfinity):

oh now you confused me so we are doing 4r^2-15r+9 right? because you wrote a totally different expression

OpenStudy (anonymous):

4r^2-15r+9 then (4)(9)=36 so 36r^2-15r+9

OpenStudy (anonymous):

and now what

OpenStudy (xapproachesinfinity):

nope that's no legible to do 36r^2-15r+9 is a different problem you have created just stop at 4x9=36 and look for all the factor that add to -15

OpenStudy (xapproachesinfinity):

factor of 36 are ?

OpenStudy (anonymous):

12 by 3

OpenStudy (xapproachesinfinity):

correct and they must be both negative -12 and -3

OpenStudy (xapproachesinfinity):

now what we do is rewrite that middle part as -15x=-12x-3x

OpenStudy (xapproachesinfinity):

that supposed to be r not x sorry

OpenStudy (xapproachesinfinity):

so the expression becomes 4r^2-12r-3r+9

OpenStudy (xapproachesinfinity):

regroup like this (4r^2-12r)-(3r-9)

OpenStudy (anonymous):

is the answer (2r-12)(2r-3)

OpenStudy (xapproachesinfinity):

then let me ask you what can i do with the first parenthesis

OpenStudy (xapproachesinfinity):

no you are going fast! do it in step to get it

OpenStudy (xapproachesinfinity):

so 4r^2-12r what can we factor

OpenStudy (anonymous):

2

OpenStudy (xapproachesinfinity):

why 2?

OpenStudy (anonymous):

4r^2

OpenStudy (anonymous):

*4r

OpenStudy (anonymous):

4r(r-3)

OpenStudy (xapproachesinfinity):

good!

OpenStudy (xapproachesinfinity):

and for this 3r-9

OpenStudy (anonymous):

3

OpenStudy (xapproachesinfinity):

yep

OpenStudy (anonymous):

(4r-3)(-3r-3)

OpenStudy (xapproachesinfinity):

no you forgettting something this is what we have so far 4r(r-3)-3(r-3)

OpenStudy (anonymous):

mmmm true

OpenStudy (anonymous):

(4r-3)(r-3)

OpenStudy (xapproachesinfinity):

yay!!

OpenStudy (anonymous):

thanks I appreciate. awesome help and way to stick with me b!

OpenStudy (xapproachesinfinity):

you did great :)

OpenStudy (xapproachesinfinity):

no problem feel free :)

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