The table below represents the velocity of a car as a function of time: The average rate of change of the function between X= 15 to X= 29 is ____ m/s to the second power and represents the car's acceleration. Please help!
for the average rate of chainge in velocity, you can imagine a line through those 2 endpoints. The slope of that is the average change over that interval
Oh so it's 2?
points (time, distance) .. (t , X)
not sure , how much time has elapsed from X=15 to X=29 on your table
42
ok, then the slope is the change in X over the change in time (29 - 15) / 42
So it's 3????
@Danjs 3?
what are the two points X=15,t=? X=29, t=?
I have no idea/:
just the slope, difference in the X, over difference in the time t (29-15) / 42 = 14/42, simploify to reduced fraction
i don't either, you have the table not me.. :)
Ohhhh X= 15 f(X)= 45 X= 29 f(X)= 87
ok then x is the time here, and f(x) is the velocity average accel = change in velocity / change in time = (87 - 45) / (29 - 15) m/s^2
So what should I put as the answer?
= 42 / 14 = 6 / 2 = 3 m/s^2
So 3? Thank you so much!
welcome
Join our real-time social learning platform and learn together with your friends!