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does the equation cube root x= 1-x have a solution? use intermediate value theorem
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HI!
to use the intermediate value theorem, make your function \[f(x)=x-\sqrt[3]{1-x}\]
if it is negative for some value of \(x\) and positive for some other value of \(x\) since it must be zero in between by the IVT
I dont understand.
I graphed the equation from both sides, but Im not sure the point where it intersects.
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?
let me look
\[f(x)=x-\sqrt[3]{1-x}\] \[f(0)=-1\\ f(9)=7\]
you can use other numbers if you like since it is negative somewhere and positive somewhere else, it must be zero in between
actually you could even use \(f(2)=3\)
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thank you so much!
could i ask you another question?
sure
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