y = (x^2+3x-4)/(x^2+5x+4)
We need to factor these first...
\(x^2+3x-4=(x+4)(x-1)\)
\(x^2+5x+4=(x+4)(x+1)\)\[y=\frac{(x+4)(x-1)}{(x+4)(x+1)}\]There is one factor on top and bottom that can cancel out, do you know what one?
OpenStudy (anonymous):
Im not sure, would it be (x+4)?
OpenStudy (anonymous):
since its the same on the top n bottom
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