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Mathematics 16 Online
OpenStudy (anonymous):

Need help with some mathmetical equations will follow and medal best answer

OpenStudy (thecalchater):

Questions?

OpenStudy (anonymous):

one sec\

OpenStudy (anonymous):

@TheCalcHater

OpenStudy (anonymous):

Ok so you need to isolate the n, the first step is to get rid of the 3 on the left side, how can you do that?

OpenStudy (anonymous):

i think the answer is -18

OpenStudy (anonymous):

Well plug it in and check, what is -2(-18)-2 all divided by 3?

OpenStudy (anonymous):

oh bye multiplying 3 i understand how to solvei just want to check

OpenStudy (anonymous):

um ok

OpenStudy (anonymous):

You're incredibly close with -18 but it's wrong, check your work, might have done a little thing wrong

OpenStudy (anonymous):

oh yeah i accidentally wrote 36 rather than 38 so -19

OpenStudy (anonymous):

Yup :)

OpenStudy (anonymous):

ok can you help me with 4 more XD @Brill

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

ok one sec

OpenStudy (anonymous):

@jdoe0001

OpenStudy (anonymous):

Thanks jdoe0001

OpenStudy (anonymous):

@jdoe0001

OpenStudy (jdoe0001):

well, one sec just so you know, it helps if you post each one in their own posting that way we can all see it anyway so, notice 4c + 16 has a common factor of 4 so \(\bf \cfrac{3}{4}(4c+16)=2c+9\implies \cfrac{3(4c+16)}{4}=2c+9 \\ \quad \\ \cfrac{3\cdot {\color{brown}{ \cancel{4}}}(c+4)}{\cancel{4}}=2c+9\) surely you can do it from there

OpenStudy (anonymous):

3*(c+4)=2c+9

OpenStudy (jdoe0001):

yeap expand and simplify :)

OpenStudy (jdoe0001):

\(\bf \cfrac{3}{4}(4c+16)=2c+9\implies \cfrac{3(4c+16)}{4}=2c+9 \\ \quad \\ \cfrac{3\cdot {\color{brown}{ \cancel{4}}}(c+4)}{\cancel{4}}=2c+9\implies 3(c+4)=2c+9 \\ \quad \\ 3c+12=2c+9\implies 3c{\color{blue}{ -2c}}=9{\color{blue}{ -12}}\implies c=?\)

OpenStudy (anonymous):

where does 12 come from

OpenStudy (anonymous):

@jdoe0001

OpenStudy (crashonce):

ur removing 12 from both sides so no change on left but right neds -12

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