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Mathematics 20 Online
OpenStudy (anonymous):

18. Use the discriminant to find the number of real solutions of the equation 3x2 – 5x + 4 = 0. Show your work.

OpenStudy (priyar):

do u know the discriminant formula?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

it islike a/ something then b / something

OpenStudy (priyar):

its D=\[\sqrt{b ^{2}-4ac}\]

OpenStudy (misty1212):

HI!!

OpenStudy (priyar):

u know what is a ,b,c right?

OpenStudy (misty1212):

actually the "discriminant" is just \[b^2-4ac\]

OpenStudy (priyar):

oh yeah no root sorry!

OpenStudy (anonymous):

would a be 3 b 5 and c 4?

OpenStudy (priyar):

almost correct!

OpenStudy (priyar):

b is -5

OpenStudy (anonymous):

okay.. after i have all that what do i do?

OpenStudy (priyar):

u just plug these values in the above expression that is \[b^2 - 4ac\]

OpenStudy (priyar):

what do u get?

OpenStudy (anonymous):

okay so i would go -5^2 -3 ?

OpenStudy (anonymous):

8?

OpenStudy (priyar):

no.. where is the "4*a*c" part?

OpenStudy (anonymous):

i don't know how to do this ?

OpenStudy (anonymous):

48

OpenStudy (priyar):

\[b ^{2}-4ac = (-5)^2 - (4*3*4)\]

OpenStudy (priyar):

yeah! 4ac is 48..what is D (as a whole)

OpenStudy (anonymous):

i don't know

OpenStudy (priyar):

D=b^2−4ac..so just evaluate the above exp i have written..

OpenStudy (priyar):

(-5)^2-48

OpenStudy (anonymous):

-58?

OpenStudy (priyar):

no.. (-5)^2=25 so 25-48=-23 ok?

OpenStudy (priyar):

@jamie2012 ?

OpenStudy (priyar):

so here D = -23

OpenStudy (anonymous):

yes. it's -23? how did you get that?

OpenStudy (priyar):

and..remember this: if D>0 -->2real roots D=0 -->2 equal real roots-->so one real root D<0 -->No real roots So what will be the answer here?

OpenStudy (priyar):

what is \[b ^{2}\] ?

OpenStudy (anonymous):

it would be 2 real roots ?

OpenStudy (priyar):

first we will clear ur doubt about -23 ok?

OpenStudy (anonymous):

okay

OpenStudy (priyar):

so what is b here?

OpenStudy (anonymous):

-5

OpenStudy (priyar):

ya..now square it

OpenStudy (priyar):

?

OpenStudy (anonymous):

can't don't know how to

OpenStudy (priyar):

squaring is multiplying the same number twice..Ex: (-2)^2 = 4

OpenStudy (priyar):

ok?

OpenStudy (anonymous):

okay

OpenStudy (priyar):

so what is (-5)^2 ?

OpenStudy (priyar):

its nothing but -5 * -5

OpenStudy (priyar):

=?

OpenStudy (anonymous):

-10

OpenStudy (priyar):

this is multiplication..not addition

OpenStudy (anonymous):

25?

OpenStudy (priyar):

yeah correct!!

OpenStudy (priyar):

so u have found b^2.. and u already told me 4ac is 48..so subtract both..

OpenStudy (priyar):

25-48

OpenStudy (anonymous):

23

OpenStudy (priyar):

no..always put the "bigger" number's sign..so its -23..

OpenStudy (priyar):

now D=-23..so is D>0 or D<0?

OpenStudy (anonymous):

i did

OpenStudy (anonymous):

d>0

OpenStudy (anonymous):

no it would be < cuz its -23?

OpenStudy (priyar):

no..D>0 means D is positive..is -23 positive?

OpenStudy (anonymous):

no it would be < cuz its -23?

OpenStudy (priyar):

ya! so what is the answer?

OpenStudy (anonymous):

d=<- 23?

OpenStudy (priyar):

why = ?

OpenStudy (priyar):

D<0 thats it

OpenStudy (anonymous):

idk..

OpenStudy (priyar):

and..remember this: if D>0 -->2real roots D=0 -->2 equal real roots-->so one real root D<0 -->No real roots So what will be the answer here?

OpenStudy (priyar):

what does D<0 mean ?

OpenStudy (priyar):

check from the above facts..

OpenStudy (anonymous):

no root

OpenStudy (priyar):

u mean no "real" root right? (coz the word real is very important..u will learn why in higher classes )

OpenStudy (anonymous):

yes i do

OpenStudy (priyar):

Good!! Thats correct!

OpenStudy (priyar):

WELL DONE!

OpenStudy (anonymous):

oh thank you so much

OpenStudy (priyar):

u r welcome!

OpenStudy (anonymous):

can you help with another one?

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