Mathematics
20 Online
OpenStudy (anonymous):
18. Use the discriminant to find the number of real solutions of the equation 3x2 – 5x + 4 = 0. Show your work.
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OpenStudy (priyar):
do u know the discriminant formula?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
it islike a/ something then b / something
OpenStudy (priyar):
its D=\[\sqrt{b ^{2}-4ac}\]
OpenStudy (misty1212):
HI!!
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OpenStudy (priyar):
u know what is a ,b,c right?
OpenStudy (misty1212):
actually the "discriminant" is just \[b^2-4ac\]
OpenStudy (priyar):
oh yeah no root sorry!
OpenStudy (anonymous):
would a be 3 b 5 and c 4?
OpenStudy (priyar):
almost correct!
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OpenStudy (priyar):
b is -5
OpenStudy (anonymous):
okay.. after i have all that what do i do?
OpenStudy (priyar):
u just plug these values in the above expression that is \[b^2 - 4ac\]
OpenStudy (priyar):
what do u get?
OpenStudy (anonymous):
okay so i would go -5^2 -3 ?
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OpenStudy (anonymous):
8?
OpenStudy (priyar):
no.. where is the "4*a*c" part?
OpenStudy (anonymous):
i don't know how to do this ?
OpenStudy (anonymous):
48
OpenStudy (priyar):
\[b ^{2}-4ac = (-5)^2 - (4*3*4)\]
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OpenStudy (priyar):
yeah! 4ac is 48..what is D (as a whole)
OpenStudy (anonymous):
i don't know
OpenStudy (priyar):
D=b^2−4ac..so just evaluate the above exp i have written..
OpenStudy (priyar):
(-5)^2-48
OpenStudy (anonymous):
-58?
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OpenStudy (priyar):
no.. (-5)^2=25
so 25-48=-23 ok?
OpenStudy (priyar):
@jamie2012 ?
OpenStudy (priyar):
so here D = -23
OpenStudy (anonymous):
yes. it's -23? how did you get that?
OpenStudy (priyar):
and..remember this:
if D>0 -->2real roots
D=0 -->2 equal real roots-->so one real root
D<0 -->No real roots
So what will be the answer here?
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OpenStudy (priyar):
what is \[b ^{2}\] ?
OpenStudy (anonymous):
it would be 2 real roots ?
OpenStudy (priyar):
first we will clear ur doubt about -23 ok?
OpenStudy (anonymous):
okay
OpenStudy (priyar):
so what is b here?
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OpenStudy (anonymous):
-5
OpenStudy (priyar):
ya..now square it
OpenStudy (priyar):
?
OpenStudy (anonymous):
can't don't know how to
OpenStudy (priyar):
squaring is multiplying the same number twice..Ex: (-2)^2 = 4
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OpenStudy (priyar):
ok?
OpenStudy (anonymous):
okay
OpenStudy (priyar):
so what is (-5)^2 ?
OpenStudy (priyar):
its nothing but -5 * -5
OpenStudy (priyar):
=?
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OpenStudy (anonymous):
-10
OpenStudy (priyar):
this is multiplication..not addition
OpenStudy (anonymous):
25?
OpenStudy (priyar):
yeah correct!!
OpenStudy (priyar):
so u have found b^2.. and u already told me 4ac is 48..so subtract both..
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OpenStudy (priyar):
25-48
OpenStudy (anonymous):
23
OpenStudy (priyar):
no..always put the "bigger" number's sign..so its -23..
OpenStudy (priyar):
now D=-23..so is D>0 or D<0?
OpenStudy (anonymous):
i did
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OpenStudy (anonymous):
d>0
OpenStudy (anonymous):
no it would be < cuz its -23?
OpenStudy (priyar):
no..D>0 means D is positive..is -23 positive?
OpenStudy (anonymous):
no it would be < cuz its -23?
OpenStudy (priyar):
ya! so what is the answer?
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OpenStudy (anonymous):
d=<- 23?
OpenStudy (priyar):
why = ?
OpenStudy (priyar):
D<0 thats it
OpenStudy (anonymous):
idk..
OpenStudy (priyar):
and..remember this:
if D>0 -->2real roots
D=0 -->2 equal real roots-->so one real root
D<0 -->No real roots
So what will be the answer here?
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OpenStudy (priyar):
what does D<0 mean ?
OpenStudy (priyar):
check from the above facts..
OpenStudy (anonymous):
no root
OpenStudy (priyar):
u mean no "real" root right? (coz the word real is very important..u will learn why in higher classes )
OpenStudy (anonymous):
yes i do
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OpenStudy (priyar):
Good!! Thats correct!
OpenStudy (priyar):
WELL DONE!
OpenStudy (anonymous):
oh thank you so much
OpenStudy (priyar):
u r welcome!
OpenStudy (anonymous):
can you help with another one?