Question

Trigonometry question

Answer 1

can't wait to see the answer to this

Answer 2

Wish i could help, but i'm to stupid for those types of questions

Answer 3

@math&ing001

Answer 4

Hmm, this one is fun, think I have an answer but I want to see what @math&ing001 has first :P

Answer 5

Since theta is neither related to x nor to y, we just check with the range.
sec has a range of \[]-\infty,-1]\cup[1,+\infty[\] so sec^2(theta) >=1
\[ \frac{ 4xy }{ (x+y)^{2} }\ge 1\] Hence 0 >= (x-y)²
So for this to be true you need x=y

Answer 6

thnks

Answer 7

no probs