Question

Help with two multiple choice questions please? #QuickHelp [will MEDAL and FAN]

Answer 1

@mathstudent55 quick help?

Answer 2

Do you know that if x-1 is a factor (or equivalently x= 1 is a root),
then sum of all the co-efficients will be = 0 ?

Answer 3

similarly,
if x+1 is the factor,
then sum of co-efficients of odd powers of x equals sum of co-efficient of even powers of x

Answer 4

example :
x^2 -2x+1
x-1 is a factor,
sum of all co-efficients = 1-2+1 = 0

x^2 +2x+1
x+1 is a factor,
sum of co-efficients of even powers of x = 1+1 = 2
sum of co-efficients of odd powers of x = 2

Answer 5

Apply these to your options of 1st question and you'll be able to eliminate 3 of them! :)

Answer 6

Sorry I had left for a moment but thanks! Lets move onto the second one.

Answer 7

sure, 2nd one is easier
if \((x-n)^p\)
is a factor, we say that 'n' is a root with the multiplicity of 'p'

Answer 8

example: if we say (x+9)^5 is a factor,
then -9 is a root with multiplicity of 5.

Answer 9

I got D for the second question

Answer 10

correct! :)

Answer 11

Ok wait lol I'm still un sure about the first one

Answer 12

what is the sum of all the co-efficients for the 1st option?

Answer 13

6

Answer 14

1-6 + 7+6 -8

that is the sum...how did you get 6?

Answer 15

You meant first as in A? I see now.

Answer 16

yeah, 1st option

Answer 17

10

Answer 18

1-6 + 7+6 -8
is actually = 0

quickly do the same for other choices.

Answer 19

except for the 3rd.
as there are 4 roots, the degree will be 4.
but the 3rd optons has degree = 3.
eliminated

Answer 20

Would it be B?

Answer 21

nopes, for b the sum isn't 0
also for d.

so x=1 could only be the root of A.

Answer 22

Oh ok I see now, thanks for your time!

Answer 23

welcome ^_^