Question

Suppose a parabola has an axis of symmetry at x=-8, a maximum height of 2, and passes through the point (-7,-1). Write the equation of the parabola in vertex form

Answer 1

Hello : )

Answer 2

the vertex form of the parabola is

y = a(x - b)^2 + c

where x = b is the axis of symmetry, c is the max or minm value of y when x = b and a is some constant

Answer 3

we know that axis of symmetry is x = -8
so that makes the equation
y = -a(x -(-8)) + c
which becomes
y = a(x + 8^2 + c

Answer 4

okay

Answer 5

now you know that c = 2 and x = -7 when y = -1

so plug in these values and find a
Thats it done

Answer 6

okay, I got y=-3(x+8)^2+2

Answer 7

thats a NOT -a v my mistake

Answer 8

okay

Answer 9

correct

Answer 10

thank you, one more?

Answer 11

plz re post

Answer 12

k