Question

help please

Answer 1

will medal:)

Answer 2

are typing still?

Answer 3

Ok so I believe what you need to do is use the equation f(x)=a(x-h)^2+k and plug in the values. The vertex is (h,k), so h=-1.5 and k=12.25 just from reading the graph. Then, take a point on the graph, I used (2,0), and plug it in for x and y. Then solve for a. When I did this, I got 0=a(2+1.5)^2+12.25 which, when solved, shows that a=-1. Then, you can write your equation in the form f(x)=a(x-h)^2+k which is f(x)=-(x+1.5)^2+12.25. Then, move around the equation so that it is in the form f(x)=Ax^2+Bx+C which is the form of a normal quadratic equation. When you do that, you get that the equation is -x^2-3x+10. Finally, factor this equation and you will have the equation of the graph in factored form!

When I factored it, I took out the -1 so I had x^2+3x-10 and when factored it is (x+5)(x-2), so I guess the equation in factored form is -(x+5)(x-2).

Sadly, after typing all of this I realized that you could just take the roots from the graph, which are x=-5 and x=2 and opposite them, then multiply them by each other to get (x+5)(x-2). Still don't know where you would get the negative in front though without solving for a..