Question

Which statement completes the syllogism?

If |x| < a for some positive number a, then x < a.
______________________________________.

If |x| < a for some positive number a, then x > –a.

If |x| < a for some positive number a, then x < a.
If |x| < a for some positive number a, then x > –a.
If x < a then x > –a.
If x > –a then x < a.

Answer 1

Hint: You might want to look up "absolute value" as a concept. If the explanation has good examples, it will show you how |x| < a has not one but two solutions.
One is x < a; the other is x > ?????

Answer 2

Thank you!