Mathematics
8 Online
OpenStudy (ohmybookness):
What is the value of 'a' for the following circle in general form?
x^2+y^2+ax+by+c=0
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OpenStudy (ohmybookness):
OpenStudy (ohmybookness):
@jinxhead20
OpenStudy (ohmybookness):
@mathstudent55 please help!!!!
OpenStudy (ohmybookness):
Last problem to my assignment.
OpenStudy (ohmybookness):
@jhonyy9 HI! I can always rely on you for help :) Can you help me with this question?
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OpenStudy (anonymous):
@AihberKhan
OpenStudy (anonymous):
@Study312
OpenStudy (anonymous):
@RhondaSommer
OpenStudy (study312):
Waht do you need jinx?
OpenStudy (study312):
what*
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OpenStudy (ohmybookness):
I just need the value of 'a' in this equation
OpenStudy (anonymous):
Its not for me its for ohmybookness
OpenStudy (anonymous):
i have no frickin idea how to do this and I wanna at least help by bringing people in here
OpenStudy (ohmybookness):
@jinxhead20 you're amazing
OpenStudy (study312):
I have no fudging idea either
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OpenStudy (anonymous):
i know what it's like to ask a question and not get help at all. I wish everybody in os was like me. It'll be 9000 times better
OpenStudy (study312):
@calculusxy @memman @Ms-Brains have any clue?
OpenStudy (anonymous):
@XhawaiiangirlX @mathstudent55 @DuranK @
RhondaSommer (rhondasommer):
firsst you have to find (h,k)
OpenStudy (aihberkhan):
Okay. So the radius is 2.
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OpenStudy (ohmybookness):
would that be the center? sorry, i have no clue ;/
OpenStudy (aihberkhan):
What is the center? @ohmybookness
OpenStudy (study312):
hey jinx what kind of puppy is that?
OpenStudy (ohmybookness):
(-4,2) ?
RhondaSommer (rhondasommer):
I got this @AihberKhan
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OpenStudy (anonymous):
golden retriever maybe
RhondaSommer (rhondasommer):
(h,k) = (3,-1)
OpenStudy (aihberkhan):
Okay so the radius is 2, which is \(r\) and the center is \(-4, 2\), which is \(h, k\).
OpenStudy (aihberkhan):
That is wrong @RhondaSommer
RhondaSommer (rhondasommer):
sorry thinking of a different circle lol
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OpenStudy (aihberkhan):
Now plug in that information to \((x - h)^2 + (y - k)^2 = r^2\)
OpenStudy (aihberkhan):
So h is \(-4\), k is \(2\) and r is \(2\).
So when plugging this all in, your final answer is \((x - (-4))^2 + (y - 2)^2 = 2^2\)
OpenStudy (ohmybookness):
so A would be 2^2?
@AihberKhan
OpenStudy (ohmybookness):
It's asking what the value of A is...
OpenStudy (anonymous):
does this question have any options @ohmybookness
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OpenStudy (ohmybookness):
nope
OpenStudy (aihberkhan):
No the center is \((a, b)\), so \(a\) would be \(-4\)
OpenStudy (aihberkhan):
Basically \(a\) is the same thing as \(h\). In my problem \(h\) was \(-4\) so that means that \(a\) is also \(-4\)
OpenStudy (ohmybookness):
Darn!! It was actually 8
OpenStudy (aihberkhan):
How, what the heck? Did it give an explanation?
@ohmybookness
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OpenStudy (anonymous):
did you get an f or something?