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Mathematics 8 Online
OpenStudy (ohmybookness):

What is the value of 'a' for the following circle in general form? x^2+y^2+ax+by+c=0

OpenStudy (ohmybookness):

OpenStudy (ohmybookness):

@jinxhead20

OpenStudy (ohmybookness):

@mathstudent55 please help!!!!

OpenStudy (ohmybookness):

Last problem to my assignment.

OpenStudy (ohmybookness):

@jhonyy9 HI! I can always rely on you for help :) Can you help me with this question?

OpenStudy (anonymous):

@AihberKhan

OpenStudy (anonymous):

@Study312

OpenStudy (anonymous):

@RhondaSommer

OpenStudy (study312):

Waht do you need jinx?

OpenStudy (study312):

what*

OpenStudy (ohmybookness):

I just need the value of 'a' in this equation

OpenStudy (anonymous):

Its not for me its for ohmybookness

OpenStudy (anonymous):

i have no frickin idea how to do this and I wanna at least help by bringing people in here

OpenStudy (ohmybookness):

@jinxhead20 you're amazing

OpenStudy (study312):

I have no fudging idea either

OpenStudy (anonymous):

i know what it's like to ask a question and not get help at all. I wish everybody in os was like me. It'll be 9000 times better

OpenStudy (study312):

@calculusxy @memman @Ms-Brains have any clue?

OpenStudy (anonymous):

@XhawaiiangirlX @mathstudent55 @DuranK @

RhondaSommer (rhondasommer):

firsst you have to find (h,k)

OpenStudy (aihberkhan):

Okay. So the radius is 2.

OpenStudy (ohmybookness):

would that be the center? sorry, i have no clue ;/

OpenStudy (aihberkhan):

What is the center? @ohmybookness

OpenStudy (study312):

hey jinx what kind of puppy is that?

OpenStudy (ohmybookness):

(-4,2) ?

RhondaSommer (rhondasommer):

I got this @AihberKhan

OpenStudy (anonymous):

golden retriever maybe

RhondaSommer (rhondasommer):

(h,k) = (3,-1)

OpenStudy (aihberkhan):

Okay so the radius is 2, which is \(r\) and the center is \(-4, 2\), which is \(h, k\).

OpenStudy (aihberkhan):

That is wrong @RhondaSommer

RhondaSommer (rhondasommer):

sorry thinking of a different circle lol

OpenStudy (aihberkhan):

Now plug in that information to \((x - h)^2 + (y - k)^2 = r^2\)

OpenStudy (aihberkhan):

So h is \(-4\), k is \(2\) and r is \(2\). So when plugging this all in, your final answer is \((x - (-4))^2 + (y - 2)^2 = 2^2\)

OpenStudy (ohmybookness):

so A would be 2^2? @AihberKhan

OpenStudy (ohmybookness):

It's asking what the value of A is...

OpenStudy (anonymous):

does this question have any options @ohmybookness

OpenStudy (ohmybookness):

nope

OpenStudy (aihberkhan):

No the center is \((a, b)\), so \(a\) would be \(-4\)

OpenStudy (aihberkhan):

Basically \(a\) is the same thing as \(h\). In my problem \(h\) was \(-4\) so that means that \(a\) is also \(-4\)

OpenStudy (ohmybookness):

Darn!! It was actually 8

OpenStudy (aihberkhan):

How, what the heck? Did it give an explanation? @ohmybookness

OpenStudy (anonymous):

did you get an f or something?

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