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Mathematics 11 Online
OpenStudy (anonymous):

HELP! Solve for x 6x-4y=3

OpenStudy (anonymous):

OpenStudy (anonymous):

I keep getting \[x=\frac{ 2y }{ 3 } + \frac{ 1 }{ 2 }\] which is none of the choices

OpenStudy (anonymous):

@LoveIt @Study312

OpenStudy (anonymous):

@AloneS

OpenStudy (anonymous):

@FibonacciChick666

jhonyy9 (jhonyy9):

6x=3 +4y x= (3+4y)/6

OpenStudy (anonymous):

ok hold on...

jhonyy9 (jhonyy9):

what you have noticed there on these choices so this is right sure - after are simplified will get this result - ok. ?

OpenStudy (sambot):

i dont understand this myself

OpenStudy (anonymous):

ok so I need to simplify the answer I keep getting then

jhonyy9 (jhonyy9):

x= 3/6 + 4y/6 x = 1/2 + 2y/3 ok. ?

jhonyy9 (jhonyy9):

@jinxhead20 yes - exactly so

OpenStudy (anonymous):

hold on working on it

OpenStudy (anonymous):

i got a

OpenStudy (anonymous):

@jhonyy9

OpenStudy (anonymous):

@ScarlettFarra2000 do you know if this is right?

jhonyy9 (jhonyy9):

@jinxhead20 you dont understand anything ?

OpenStudy (anonymous):

tbh no! sorry for being dumb and wasting your time.

OpenStudy (anonymous):

I've read this lesson over 9000 time (metaphor) and I still dont get it.

OpenStudy (anonymous):

nobody's perfect. you and your fellow geniuses and moderators should learn that. That'll make os a better place

OpenStudy (anonymous):

even preetha treats people who have an ss below 80 like crap im sick of it

OpenStudy (astrophysics):

\[6x-4y=3\] so the idea, for what you can think of right now is, we apply the opposite operation of what already exists to cancel something in algebra. So looking at your question we need to solve for x, that means get x by itself. Now the first thing you want to do is get rid of that annoying -4y, so we say hey how can we do that? Lets try adding 4y to both sides and see what happens! \[6x-4y\color{red}{+4y}=3\color{red}{+4y} \implies 6x=3+4y\] notice what we do to one side we must do it to the other, so what should we do next? :)

OpenStudy (astrophysics):

And the 4y's on the left get cancelled out

jhonyy9 (jhonyy9):

@jinxhead20 look please 6x=3 +4y - you have got this - yes :- so divide both sides by 6 - what will get ? 6x --- = (3/6) + (4y)/6 so on the left side simplifie 6 by 6 and remain there just x - so on 6 the right side 3/6 = 1/2 after simplifie it by 3 - yes ? so (4y/6) = (2*2y)/(2*3) = 2y/3 after simplifie there 2 by 2 - yes ? - so hope now will understand how we get this result - ok. ? x= (3+4y)/6

OpenStudy (astrophysics):

\(\color{blue}{\text{Originally Posted by}}\) @jinxhead20 I keep getting \[x=\frac{ 2y }{ 3 } + \frac{ 1 }{ 2 }\] which is none of the choices \(\color{blue}{\text{End of Quote}}\) Hey this is right

jhonyy9 (jhonyy9):

@jinxhead20 - do you understand it now ?

OpenStudy (anonymous):

ok I'm getting there but here's what I don't get

OpenStudy (astrophysics):

\[A+B = B+A\]

OpenStudy (anonymous):

@Astrophysics WHY DO I KEEP GETTING THAT ANSWER! THERE'S NO WAY I CAN SIMPLIFY IT LIKE jHNONNY SAID!

OpenStudy (astrophysics):

Your answer is correct

OpenStudy (anonymous):

but it matches none of the choices in the atachment no matter what i do

OpenStudy (astrophysics):

\[6x = 3+4y \implies \frac{ (3+4y) }{ 6 } \implies \frac{ 3 }{ 6 }+\frac{ 4y }{ 6 } \implies \frac{ 1 }{ 2 }+\frac{ 2 }{ 3 }y\]

OpenStudy (anonymous):

look jhonnoy I know ur pissed so why dont you just go and report me to ur little moderator friends

OpenStudy (astrophysics):

It's the same thing as I said above A+B = B+A

OpenStudy (anonymous):

OMG THANKS!

OpenStudy (astrophysics):

\[\frac{ 2 }{ 3 }y+\frac{ 1 }{ 2 } = \frac{ 1 }{ 2 }+\frac{ 2 }{ 3 }y\]

OpenStudy (astrophysics):

:)

jhonyy9 (jhonyy9):

@jinxhead20 x=2y/3+1/2 so this is same like x= 1/2 + 2y/3

OpenStudy (astrophysics):

Don't doubt yourself @jinxhead20 you're getting it!

OpenStudy (anonymous):

See I said a before but jhnooy was like "you dont understand?" I was right this whole time i cant believe it

OpenStudy (astrophysics):

Please don't focus on the negativity, just ignore and keep trying! Good luck!

OpenStudy (anonymous):

ok :)

jhonyy9 (jhonyy9):

was my pleasure good luck bye

jhonyy9 (jhonyy9):

@jinxhead20 you have blocked me ? why ? i just wan help you realy true for you can learning how you solve same exercises - ok . than you like it so ?--- bye

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