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Help on linear inequalities please, thank you!
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If x,y,z≥0, 3y+2z=3+x, 3y+z=4-3x, find the largest and smallest value of 3x-3y+4z
On rearranging equation 3y+z=4-3x, we get 3x + 3y + z = 4 This equation will not hold true for any values of x,y and z if x,y,z≥0. Hence, we cannot obtain values of x, y and z ( or the question is wrong!).
I think the question is correct
Sorry I am not sure! :/
sokay thanks!!
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:)
edit: the question actually says (x2+ax+b)^10 is actually = with one more line on top. NOt sure if it's a typo though
@ganeshie8 @pooja195
means i can't understand what you mean can you draw it to show perfectly
|dw:1454024986516:dw| that's the sign
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