Question

How to solve b^2=-6-7b

Answer 1

flip the problem around

Answer 2

How do I do that

Answer 3

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

b^2-(-6-7*b)=0

Answer 4

Is that they answer

Answer 5

Factoring b2+7b+6

The first term is, b2 its coefficient is 1 .
The middle term is, +7b its coefficient is 7 .
The last term, "the constant", is +6

Step-1 : Multiply the coefficient of the first term by the constant 1 • 6 = 6

Step-2 : Find two factors of 6 whose sum equals the coefficient of the middle term, which is 7 .

-6 + -1 = -7
-3 + -2 = -5
-2 + -3 = -5
-1 + -6 = -7
1 + 6 = 7 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 1 and 6
b2 + 1b + 6b + 6

Step-4 : Add up the first 2 terms, pulling out like factors :
b • (b+1)
Add up the last 2 terms, pulling out common factors :
6 • (b+1)
Step-5 : Add up the four terms of step 4 :
(b+6) • (b+1)
Which is the desired factorization

Answer 6

b^2=-6-7b is an example of a very important category of math function: It's a quadratic.
What does a quadratic equation look like when written in standard form? b^2=-6-7b needs to be re-written in descending powers of b.

Answer 7

I'm lost

Answer 8

here is the answer b^2-(-6-7*b)=0 do you understand

Answer 9

Thx for the but no I don't I sux at math

Answer 10

Suck

Answer 11

all you practically do is flip it around

Answer 12

Wat about this one b^2-9=0

Answer 13

b^(2)-(9)=0 so just rearrange and your answer should be b=3

Answer 14

is that good