Question

Assume f is the function defined by
2t+9 if t<0
3t-10 if t≥0

Evaluate f(1)

Answer 1

1 > 0

3t- 10 t >= 0 ( plug here)

f(1) = 3 * 1 - 10 = -7

Answer 2

here t > 0
so use the second expression 3t - 10

Answer 3

im a little confused. how come you used the second expression? @TrojanPoem

Answer 4

It asks to evaluate the expression when t = 1

f(1)

the given intervals are

2t + 9 when t is smaller than zero
3t- 10 when t is greater than zero

1 is greater than zero

so we pick the second as our f(t)

Answer 5

oh i see. Thank you!

Answer 6

you're welcome.

Answer 7

so what if it now says evaluate f(|x|+1) @TrojanPoem ?

Answer 8

f(x+1) x > 0 , f(-x+1) x < 0

Answer 9

i have to plug it in for both?

Answer 10

yeah