Question

Solve the system using the substitution method.
y-3x=2 and y=(x+1)^2-5

Answer 1

So y is already isolated for you in the second equation,
so substitute (x+1)^2-5 into the first equation

Answer 2

\[y-3x=2 \\
y=(x+1)^2-5\] right?

Answer 3

first equation solve for \(y\) get \[y=3x+2\]

Answer 4

^2-5

Answer 5

next step is to set them equal and write \[(x+1)^2-5=3x+2\] which is a quadratic equation
do you know how to solve it?

Answer 6

thank you so much!!