Question

find the zeroes and state the multiplicity of multiple zeroes
y=(x+1)^2 (x-1) (x-2)

Answer 1

do you know when will be this equation equal zero ?

Answer 2

so when one from these factors will be equal zero

so do you know how you get the zeroes of these factors ?

Answer 3

no

Answer 4

so in this way --- separated make every parentheses equal zero :

(x+1)^2 = 0 -and solve it for x

same like the first

x-1=0

and

x-2=0

Answer 5

can you solve it ?

Answer 6

x=1
x=1
x=2

Answer 7

x=-1

Answer 8

no

step by step

1. (x+1)=0

Answer 9

sorry

(x+1)^2 =0

Answer 10

courage - this is easy

Answer 11

is it not -1

Answer 12

so (x+1)^2 =0

yes x=-1 is right

Answer 13

ok

Answer 14

how do i find the multiplicities

Answer 15

but there are again two zeroes what you need calculi again

Answer 16

x=-1 is the first one you need getting again two

Answer 17

getting again two?

Answer 18

just make equal zero the second and 3rd parentheses and calculi for x

Answer 19

exactly how you have solved the first

Answer 20

x=1
x=2

Answer 21

x-1=0
x=?

Answer 22

1

Answer 23

yes 1 and 2 right sure

Answer 24

so than now what are zeroes of this equation ?

Answer 25

-1, 1, 2

Answer 26

yes - and what mean multiplicity of them ?

Answer 27

i dont know what that means