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Find the center and the radius of the following circle: x^2 + y^2 - 6x + y = 3 Best explanation/answer earns medal!
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we can do this by completing the square to convert the equation to the form (x - a)^2 + ( y - b)^2 = r^2 Are you familiar with completing the square?
i think so, i have the answers in my notes, but i'm just trying to remember what i did to get that answer
Right now i have (x-3)^2 + (y + .5)^2
x^2 - 6x = (x - 3)^2 - 9
what about the y value?
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y^2 + y = (y + 0.5)^2 - 0.25
so the center of the circle is (3,-.5) how do i find the radius?
(x - 3)^2 + (y + 0.5)^2 = 3 + 9 + 0.25 = 12 .25 r^2 = 12.25 r = ?
3.5??
yep
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oh okay cool!
yw
thanks!
yw
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