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Mathematics 8 Online
OpenStudy (day00):

Solve the following polynomial equation: x^3+3x^2-x-3=0?

RhondaSommer (rhondasommer):

what do you think?

OpenStudy (welshfella):

one root is pretty obvious. can you see what it is . Its a very small number...

OpenStudy (welshfella):

plug it in for x and see iff the expression works out to 0

OpenStudy (welshfella):

also you might try factoring in groups

OpenStudy (mathmale):

I agree with welshfella. Look at the constant term; it is -3. What are the four possible factors of -3? He's suggesting you try these one by one until you determine which is a root of the given equation.

OpenStudy (welshfella):

yes

OpenStudy (mathmale):

Leaving the 3rd and 4th terms alone, factor the 1st and 2nd terms as much as possible. What factor do these 2 terms ahve in common?

OpenStudy (mathmale):

x^3+3x^2-x-3=0?

OpenStudy (mathmale):

First of all, please stop saying, "I suck at math." Saying that will not improve your math skills; study and practice will. Neither does "I suck at math" earn you sympathy. You must solve x^3+3x^2-x-3=0. this is a "third order polynomial" because the highest power of x is 3. You could choose from several different approaches to solve this. Among them are (1) factoring, (2) factoring by grouping, (3) synthetic division. Look at the last term of your equation, on the left. What is it?

OpenStudy (mathmale):

Have you had any experience with "synthetic division?"

OpenStudy (day00):

I'm going to go with factoring by grouping

OpenStudy (mathmale):

Here is what I'd suggested about thirty minutes ago: "Leaving the 3rd and 4th terms alone, factor the 1st and 2nd terms as much as possible. What factor do these 2 terms ahve in common?"

OpenStudy (day00):

Ok thanks

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