Question

solve equation e^x + 24e^−x − 10 = 0

Answer 1

2 solutions one is x=ln6\2 other is ln4\2

Answer 2

@amity how?

Answer 3

Multiply be \(e^{x}\), which never is 0, and it should take on the appearance of something quadratic.

Answer 4

Let e^x=y,then equation is y+24/y=10,,,,that is y^2-10y+24=0

Answer 5

Let e^x=y,then equation is y+24/y=10,,,,that is y^2-10y+24=0

Answer 6

I still don't understand this question. Am I supposed to get two answers?

Answer 7

Factor is y^2-6y-4y+24=0,,,y(y-6)-4(y-6)=0,,,(y-4)(y-6)=0,,..which yields y=6, y=4,,,e^x is 4 and 6

Answer 8

Factor is y^2-6y-4y+24=0,,,y(y-6)-4(y-6)=0,,,(y-4)(y-6)=0,,..which yields y=6, y=4,,,e^x is 4 and 6