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Mathematics 18 Online
OpenStudy (baewolfstar):

http://i.imgur.com/lziFe7N.png i forgot how to work this out??

OpenStudy (phi):

you can write \[ \sqrt{a\cdot b}= \sqrt{a} \cdot \sqrt{b} \] and vice versa in other words, you can multiply the square root part. what do you get ?

OpenStudy (baewolfstar):

@phi i got 5.6637

OpenStudy (luigi0210):

Without estimating, try using Phi's method: \(\Large 6\sqrt{7}*2\sqrt{21} \) \(\Large 6\sqrt{7}*2\sqrt{7*3} \) \(\Large (6*2)\sqrt{\color{red}{7*7}*3} \) When there is a perfect square, you are allowed to remove it: \(\Large (6*2*7)\sqrt{3} \)

OpenStudy (baewolfstar):

ohh thanks sorry im so bad at this lol

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