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http://i.imgur.com/lziFe7N.png i forgot how to work this out??
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you can write \[ \sqrt{a\cdot b}= \sqrt{a} \cdot \sqrt{b} \] and vice versa in other words, you can multiply the square root part. what do you get ?
@phi i got 5.6637
Without estimating, try using Phi's method: \(\Large 6\sqrt{7}*2\sqrt{21} \) \(\Large 6\sqrt{7}*2\sqrt{7*3} \) \(\Large (6*2)\sqrt{\color{red}{7*7}*3} \) When there is a perfect square, you are allowed to remove it: \(\Large (6*2*7)\sqrt{3} \)
ohh thanks sorry im so bad at this lol
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