Question

You have two exponential functions. One function has the formula g(x) = 3(2x). The other function has the formula h(x) = 2x+1. Which option below gives formula for k(x) = (g – h)(x)?
k(x) = 2x
k(x) = 5(2x)
k(x) = 5(2x+1)
k(x) = 2

Answer 1

Are the functions

\(g(x) = 3(2^x)\)

and

\(h(x) = 2^{x + 1} \) ?

You need to write equations clearly, so we don't have to waste time trying to guess what they are. The second function can also be

\(h(x) = 2^x + 1\)

How do we know what you mean?

Use the ^ (the caret symbol) to mean an exponent and use parentheses where needed.

Answer 2

You can also use the equation editor, the draw tool, or post a picture.

Answer 3

You have two exponential functions. One function has the formula g(x)=3(2^x). The other function has the formula h(x)=2^x+1. Which option below gives the formula for k(x)=(g-h)(x)
a) k(x)=2^x
b) k(x)=5(2^x)
c) k(x)=5(2^x+1)
d) K(x)=2

Answer 4

hmmm should be a 2 there

so hmm keep in mind that \((g-h)(x)\iff g(x)-h(x)\qquad
\begin{cases}
g(x)=3(2^x)\\
h(x)=2^x+1
\end{cases}
\\ \quad \\
g(x)-h(x)\implies [3(2^x)]\quad -\quad [2^x+1]\)