Question

What equation has a graph that is perpendicular to the graph of -x+6y=-12. Can you please show me how this is done

Answer 1

hi i can be a little help!:)

Answer 2

1. Find the slope of -x+6y=-12.
2. Find the negative reciprocal of this line, to pin down the slope of the perpendicular line.
3. Write (in slope-intercept form) the equation y=mx+b.
Choose any value you want for b. m, the slope, must be the negative reciprocal of the slope of -x+6y=-12.

Answer 3

There are several answers. I am trying to help my son and am so confusedWhich equation has a graph that is perpendicular to the graph of −x + 6y = −12?

A. x + 6y = −67
B. x − 6y = −52
C. 6x + y = −52
D. 6x − y = 52

Answer 4

I cannot figure out how to get the answer. It's been a long time

Answer 5

I am getting y=1/6x-2 so then would the negative reciprical be -6 OMG so confused

Answer 6

Solve −x + 6y = −12 for y: First, add x to both sides to move the -x to the right side of the equation. You should get 6y=x-12.

Your slope is correct: 1/6. Yes, and the neg recip is indeed (-6).

y=mx + b. Use -6 for the slope m and choose any value you wish for b. That'll give you the answer you and your son wanted.

Answer 7

I have absolutely no clue where they are getting the 52 or the 67

Answer 8

we chose B, but that was incorrect

Answer 9

Remember, the value of b is arbitrary. You need to choose the answer that is most likely.
Answers A and B have the wrong slope.

You have y =-6x + b.

Move the 6x to the left side by adding 6x to both sides.

6x+y=b. b is arbitrary. Which answer choice is correct?

Answer 10

so, the answer would be C?

Answer 11

Yes, indeed. Nice work. Discuss our reasoning with your son. Wish I were there to help with that. Have to get off the 'Net now, but will be on again later tonight. Take care.

Answer 12

Thanks! I was confusing myself with the numbers!!! Appreciate the help!

Answer 13

For your information,
when the given equation is in the form
Ax+By+C=0
or
Ax+By=C,
A line perpendicular to the given can be found by
1. switch the coefficients of x and y
2. change the sign of ONE of the coefficients.

Example:
Find a line perpendicular to
4x-3y=8...........(1)
A line perpendicular to (1) is
3x+4y=8...........(2)
The constant term 8 does not change the slope.
Sometimes you need to adjust the constant term to pass through a given point.

Answer 14

Thanks!